2015: d24: ex2: add solution
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2015/d24/ex2/ex2.py
Executable file
71
2015/d24/ex2/ex2.py
Executable file
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#!/usr/bin/env python
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import itertools
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import math
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import sys
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from collections.abc import Iterator
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def solve(input: str) -> int:
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def parse(input: str) -> list[int]:
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return [int(n) for n in input.splitlines()]
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def package_groups(
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packages: list[int],
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) -> Iterator[tuple[list[int], list[int], list[int], list[int]]]:
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assert sum(packages) % 4 == 0 # Sanity check
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target_weight = sum(packages) // 4
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# I'm lazy, a brute-force triple loop is good enough
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found = False
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for first_len in range(1, len(packages) + 1):
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for perm in itertools.combinations(range(len(packages)), first_len):
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first = [packages[p] for p in perm]
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if sum(first) != target_weight:
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continue
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others = [p for i, p in enumerate(packages) if i not in perm]
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for sec_len in range(1, len(others) + 1):
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for perm in itertools.combinations(range(len(others)), sec_len):
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second = [others[p] for p in perm]
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if sum(second) != target_weight:
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continue
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others_ = [p for i, p in enumerate(others) if i not in perm]
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for third_len in range(1, len(others_) + 1):
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for perm in itertools.combinations(
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range(len(others_)), third_len
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):
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third = [others_[p] for p in perm]
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last = [
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others_[i]
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for i in range(len(others_))
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if i not in perm
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]
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yield first, second, third, last
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# We only care to enumerate all valid *first* packages
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# Not *all* permutations
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found = True
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break
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if found:
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break
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if found:
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break
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if found:
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break
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# *Don't* break if `found`, we want to keep enumerating this length
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if found:
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break
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def quantum_entanglement(packages: list[int]) -> int:
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return math.prod(packages)
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packages = parse(input)
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return min(quantum_entanglement(split[0]) for split in package_groups(packages))
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def main() -> None:
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input = sys.stdin.read()
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print(solve(input))
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if __name__ == "__main__":
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main()
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