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abacus: bignum: add division & modulo

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Like the C language, the `%` operator is rather the remainder, such that
`(a/b)*b + (a%b) = a`.

I still call it modulo though...
This commit is contained in:
Bruno BELANYI 2021-08-21 01:51:33 +02:00
parent 7cd0664e60
commit 4e3d53ecd4
3 changed files with 151 additions and 0 deletions
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27
src/bignum/bignum.hh
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@ -62,6 +62,31 @@ public:
return ret;
}
friend BigNum& operator/=(BigNum& lhs, BigNum const& rhs) {
lhs.divide(rhs);
return lhs;
}
friend BigNum operator/(BigNum const& lhs, BigNum const& rhs) {
auto ret = lhs;
ret /= rhs;
return ret;
}
friend BigNum& operator%=(BigNum& lhs, BigNum const& rhs) {
lhs.modulo(rhs);
return lhs;
}
friend BigNum operator%(BigNum const& lhs, BigNum const& rhs) {
auto ret = lhs;
ret %= rhs;
return ret;
}
friend std::pair<BigNum, BigNum> div_mod(BigNum const& lhs,
BigNum const& rhs);
friend bool operator==(BigNum const& lhs, BigNum const& rhs) {
return lhs.equal(rhs);
}
@ -98,6 +123,8 @@ private:
void add(BigNum const& rhs);
void substract(BigNum const& rhs);
void multiply(BigNum const& rhs);
void divide(BigNum const& rhs);
void modulo(BigNum const& rhs);
bool equal(BigNum const& rhs) const;
bool less_than(BigNum const& rhs) const;